Chemistry – How to Determine the Number of Bonds in an Element

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In order to determine the number of links that an element will form, you must determine its load. Once you know the load, you know the obligations because, for the most part, the number of bonds is equal to the absolute value of the load. Let's learn how to determine the charge or the number of oxidation of an atom.

First, you will need to gather some tools to help you in your task. You will need a periodic table, the byte rule and some physics concepts. You can get a periodic table of your book, your teacher or online and the byte rule is below.

The rule of the byte:

An element will tend to gain or lose electrons in order to obtain a noble gas valence.

Physics concepts:

Nature tends to evolve towards a lower energy state, which basically means that nature is easy. In addition, you must remember that opposites attract and reject likes. These two concepts will help you determine if an element will gain or lose electrons to get the noble gas valence.

Well, ready to put these tools to work? Good! Used to determine the charge for lithium.

  • Find lithium on the periodic table and determine the valence electrons.
  • Lithium has 1 valence electron.

Now remember the byte rule and ask: "Is it easier to lose an electron and go back to helium or is it easier to gain 7 electrons and move to the neon?"

I hope you answered that it is easier to lose one and go back. Thus, lithium will tend to lose an electron and become a cation (1+).

Remember that if you lose electrons, you become more positive and if you gain electrons, you become more negative because the electrons are negative.

If the lithium charge is (1+) then it will have a bond. It's as simple as that.

Should we try another one? What about chlorine?

  • Find the chlorine on the periodic table and determine the valence electrons.
  • Chlorine has 7 valence electrons.

Now ask, "Is it easier to gain 1 electron and go to argon or is it easier to lose 7 electrons and go back to neon?"

This is true, it is easier to win one and move to argon. Thus, the chlorine will have a charge (1-) and will form a bond.


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